1.75x^2+72x=624

Solution for 1.75x^2+72x=624 equation:

1.75x^2+72x=624

We move all terms to the left:

1.75x^2+72x-(624)=0

a = 1.75; b = 72; c = -624;
Δ = b2-4ac
Δ = 722-4·1.75·(-624)
Δ = 9552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9552}=\sqrt{16*597}=\sqrt{16}*\sqrt{597}=4\sqrt{597}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-4\sqrt{597}}{2*1.75}=\frac{-72-4\sqrt{597}}{3.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+4\sqrt{597}}{2*1.75}=\frac{-72+4\sqrt{597}}{3.5}
$